Sign up ×
Webmasters Stack Exchange is a question and answer site for pro webmasters. It's 100% free, no registration required.

I've recently downloaded my usage reports from my EC2 account, but I don't understand the 'UsageValue' data since there is no indication of what unit the numbers are measured in.

I have a similar problem with the UsageValue - $ conversion rate data.

Searching online I couldn't really find a working calculator or conversion tool.

Can the community advise how to calculate my estimated bill from a usage report?

share|improve this question

migrated from Aug 31 '11 at 12:06

This question came from our site for power users of web applications.

You may want to post a statement so those of us who haven't seen one can try to help. – John Conde Aug 31 '11 at 12:08

1 Answer 1

up vote 2 down vote accepted

You may have better luck with your question at the AWS Developer forum and I think this thread may be helpful to you

Partial quote from thread linked to above.

"EC2 data transfer usage will be given in bytes for each type of Data Transfer (for eaxmple, DataTransfer-Regional-Bytes, DataTransfer-Out-Bytes or DataTransfer-In-Byte).

Regarding inbound data transfers, on December 8, 2009, we announced free inbound data transfers to AWS through June 2010. You can read the article here:

We also post data transfer pricing on the detail page for each Amazon Service. For EC2 data transfer pricing, please review the EC2 pricing details here:

There is no Data Transfer charge between Amazon EC2 and other Amazon Web Services (like S3) within the same region (i.e. between Amazon EC2 US West and Amazon S3 in US West). Data transferred between Amazon EC2 instances located in different Availability Zones in the same Region will be charged Regional Data Transfer. Data transferred between AWS services in different regions will be charged as Internet Data Transfer on both sides of the transfer.

Data transfers between separate AWS Regions, or via public IP addresses will be charged at the normal rate."

Quote from Daryl W on this thread.

share|improve this answer

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.